(D^2+2D+1)y(t)=1

Solution for (D^2+2D+1)y(t)=1 equation:

Simplifying
(D2 + 2D + 1) * y(t) = 1

Reorder the terms:
(1 + 2D + D2) * y(t) = 1

Reorder the terms for easier multiplication:
y * t(1 + 2D + D2) = 1

Multiply y * t
ty(1 + 2D + D2) = 1
(1 * ty + 2D * ty + D2 * ty) = 1
(1ty + 2tyD + tyD2) = 1

Solving
1ty + 2tyD + tyD2 = 1

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Reorder the terms:
-1 + 1ty + 2tyD + tyD2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 1ty + 2tyD + tyD2 = 0

The solution to this equation could not be determined.